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    Calculus (University Level)

    Improper Integral (1/xᵖ, 1 to ∞)

    Determine convergence and value of ∫[1,∞] x^(−p) dx.

    Standard Formula
    ∫[1,∞] 1/xᵖ dx = 1/(p−1) if p > 1, else diverges

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    p
    120
    Live EquationFormula Proof
    ∫[1,∞] 1/xᵖ dx = 1/(2−1) if 2 > 1, else diverges = 1
    Area Under Curve ∫f(x)dx
    Calculated Solution
    1

    Direct computational model evaluating Improper Integral (1/xᵖ, 1 to ∞).

    Variable Mechanics

    Roles, constraints & impacts

    1 Params
    p

    Exponent p (must be > 0)

    Exponent p (must be > 0)

    ImpactPrimary formula parameter
    ConstraintReal number

    At a Glance

    Gotchas, units & real-world use

    Essential

    Formula Nature & Mechanics

    Direct computational model evaluating Improper Integral (1/xᵖ, 1 to ∞).

    Common Mistakes & Traps

    • Ensure all input measurements share consistent units before calculating.
    • Check for denominator values approaching zero to prevent undefined division.
    • Follow standard order of operations (PEMDAS: Parentheses, Exponents, Multiply/Divide, Add/Subtract).

    Dimensional Analysis & Units

    Direct evaluation matching formula variable dimensions.

    Real-World & Industry Application

    Widely utilized across modern calculus applications, academic analysis, and engineering estimations.

    📖 Beginner's guideImproper Integrals: Convergence and the p-TestLearn what an improper integral is, when ∫1/xᵖ from 1 to ∞ converges, and how to find its value, with a free calculator with step-by-step solutions.

    Worked Example: Improper Integral (1/xᵖ, 1 to ∞)

    Given:

    • p = 2
    1. ∫[1,∞] 1/x² dx
    2. = [−1/x]₁^∞ = 0 − (−1) = 1

    Answer: 1

    Frequently Asked Questions

    What is the Improper Integral (1/xᵖ, 1 to ∞) formula?

    ∫[1,∞] 1/xᵖ dx = 1/(p−1) if p > 1, else diverges. Determine convergence and value of ∫[1,∞] x^(−p) dx.

    How do I calculate Improper Integral (1/xᵖ, 1 to ∞)?

    Enter Exponent p (must be > 0) (p) into the calculator. It applies ∫[1,∞] 1/xᵖ dx = 1/(p−1) if p > 1, else diverges and shows every step of the working.

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